A positively charged particle starts at rest 25 cm from a second positively charged particle, which is held stationary throughout the experiment. The first particle is released and accelerates directly away from the second particle. When the first particle has moved 25 cm, it has reached a velocity of `10(sqrt2)ms^(-1)` . What is the maximum velocity `(in xx 10 ms^(-1))` that the first particle will reach?

Explanation

To solve the problem, we will use the principle of conservation of energy. The potential energy of the system will be converted into kinetic energy as the charged particle moves away from the stationary charged particle.

### Step-by-step Solution:

1. **Identify Initial Conditions**:
- The first positively charged particle starts at rest, 25 cm from the second positively charged particle.
- The initial distance \( R = 25 \) cm = 0.25 m.
- The first particle is released and accelerates directly away from the second particle.
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