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Two equal point charges are fixed at x=-...

Two equal point charges are fixed at `x=-a` and `x=+a` on the x-axis. Another point charge Q is placed at the origin. The change in the electrical potential energy of Q, when it is displaced by a small distance x along the x-axis, is approximately proportional to

A

`x`

B

`x^2`

C

`x^3`

D

`1//x`

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the change in electrical potential energy of the charge \( Q \) when it is displaced a small distance \( x \) along the x-axis. Here’s a step-by-step solution: ### Step 1: Initial Setup We have two equal point charges \( +q \) fixed at positions \( x = -a \) and \( x = +a \) on the x-axis. A charge \( Q \) is placed at the origin \( (x = 0) \). ### Step 2: Calculate Initial Potential Energy The potential energy \( U \) of charge \( Q \) due to the two point charges can be calculated using the formula for potential energy between point charges, which is given by: \[ ...
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