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Conisder an electric field vecE=E0hatx w...

Conisder an electric field `vecE=E_0hatx` where `E_0` is a constant .
The flux through the shaded area (as shown in the figure) due to this field is

A

`2E_0a^2`

B

`sqrt2E_0a^2`

C

`E_0a^2`

D

`(E_0a^2)/(sqrt2)`

Text Solution

Verified by Experts


`vecA=Acos45^(@)hati-Asin45^(@)hatk`
`=sqrt(2)a^(2)(1)/(sqrt(2))hati-sqrt(2)a^(2)(1)/(sqrt(2))hatk=a^(2)hati-a^(2)hatk`
`phi=vecE.vecA=E_(0)hati.(a^(2)hati-a^(2)hatk)=E_(0)a^(2)`
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