Home
Class 12
PHYSICS
A charge +q is fixed at each of the poin...

A charge `+q` is fixed at each of the points `x=x_0`, `x=3x_0`, `x=5x_0`,…………`x=oo` on the x axis, and a charge `-q` is fixed at each of the points `x=2x_0`, `x=4x_0`, `x=6x_0`, …………`x=oo`. Here `x_0` is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be `Q//(4piepsilon_0r)`.Then, the potential at the origin due to the above system of

A

0

B

`q/(8piepsilon_0x_01n 2)`

C

`oo`

D

`(q 1n 2)/(4piepsilon_0x_0)`

Text Solution

AI Generated Solution

To find the electric potential at the origin due to the given system of charges, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Charges and Their Positions:** - Positive charges `+q` are located at positions `x = x_0`, `x = 3x_0`, `x = 5x_0`, ..., which are at odd multiples of `x_0`. - Negative charges `-q` are located at positions `x = 2x_0`, `x = 4x_0`, `x = 6x_0`, ..., which are at even multiples of `x_0`. ...
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise Assertion and Reason Type|8 Videos

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS ENGLISH|Exercise Comprehension Type|94 Videos

  • MAGNETIC FIELD AND MAGNETIC FORCES

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct Answer type|2 Videos

  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS ENGLISH|Exercise Integer|12 Videos

Similar Questions

Explore conceptually related problems

Show that electric potential at a point P, at a distance .r. from a fixed point charge Q, is given by : V=(1/(4piepsilon_0))Q/r

(a) The charges each Q are placed at x - d , 2d , 4d ,…oo . Find electric potential at origin O . (b) A charge +Q is placed at each of the points x = d , x = 3d ,x = 5d ,…..,oo on the x -axis , and a charge -Q is placed at each of the points x = 2d , x = 4d , x= 6d , ...,oo .Find the electric potential at the origin O .

Along the x-axis, three charges q/2,-q and q/2 are placed at x=0,x=a and x=2a respectively. The resultant electric potential at a point P located at a distance r from the charge -q , (rgtgta) is : ( epsilon_(0) is the permittivity of free space)

Two point charges Q and -Q/4 are separated by a distance x.

Three charges are placed along x- axis at x = -a , x=0 and x=a as shown . Calculate the potential energy of the system.

Two point charges q each are fixed at (a,0) and (-a,0). A third charge Q is placed at origin. Electrons potential energy of the system will

Potential at a point x-distance from the centre inside the conducting sphere of radius R and charged with charge Q is

The electric potential decreases uniformly from V to -V along X-axis in a coordinate system as we moves from a point (-x_(0), 0) to (x_(0), 0) , then the electric field at the origin:

Two equal positive charges Q are fixed at points (a, 0) and (-a,0) on the x-axis. An opposite charge -q at rest is relased from point (0, a) on the y-axis. The charge -q will

Infinite charges of magnitude q each are lying at x= 1,2,4,8….meter on X -axis. The value of intensity of electric field at point x=0 due to these charges will be