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A charge +Q is fixed at the origin of th...

A charge `+Q` is fixed at the origin of the co-ordinate system while a small electric dipole of dipolement `vecp` pointing away from the charge along the x-axis is set free from a point far away from the origin.
(a) Calculate the K.E. of the dipole when it reaches to a point (d, 0).
(b) Calculate the force on the charge `+Q` at this moment.

A

`3/(4piepsilon_0)(pq)/(d^2)`

B

`3/(2piepsilon_0)(pq)/(d^2)`

C

`1/(2piepsilon_0)(pq)/(d^2)`

D

`1/(4piepsilon_0)(pq)/(d^2)`

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To solve the problem, we will break it down into two parts as specified in the question. ### Part (a): Calculate the K.E. of the dipole when it reaches a point (d, 0). 1. **Understanding the Potential Due to the Dipole**: The potential \( V \) due to an electric dipole at a distance \( r \) is given by: \[ V = \frac{1}{4 \pi \epsilon_0} \frac{\vec{p} \cdot \hat{r}}{r^2} ...
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