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In the given circuit , when key K is ope...

In the given circuit , when key K is open, reading of ammeter is I. Now key K is closed, then the correct statement is

A

If `epsilon_1 lt IR`, reading og the ammeter is less than I.

B

If `IR gt epsilon_1`, reading of the ammeter is greater than I.

C

If `epsilon_1 gt 2IR`, reading og the ammeter will be zero.

D

Reading of ammeter will not change.

Text Solution

Verified by Experts

The correct Answer is:
B
b. `R(i_1 + i_2) = E_1`
`i_2R + (i_1 + i_2) R = E_2`
`i_2 = (E_2 - E_1)/R `
[Initially, `E = E_2//R`].
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