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The switch S in the circuit diagram is c...

The switch S in the circuit diagram is closed at t = 0. The charge on capacitors at any time is

A

`q_(t) = EC(1-e^(-2t//3RC))`

B

`q_(t) = EC(1-e^(-t//2RC))`

C

`q_(t) = EC(1-e^(-t//3RC))`

D

`q_(t) = EC(1-e^(-3t//2RC))`

Text Solution

Verified by Experts

The correct Answer is:
C
c. Applying KVL, we get
`1/2 = (dq)/(dt) or I = 2 (dq)/(dt)`
`E - IR -1/2R - q/C = 0`
or `E -3/2 IR - q/C =0 `
or `E - 3/2 xx 2 (dq)/(dt) R - q/C = 0`
`q_(t) = EC(1-e^(-t//3RC))`.
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