Given that current through `CA = 1A`, current through `C'A' = 2A`/ Now if A is connected to A' and B is connected B'. Find currents through CA and C'A', respectively.

Options

A. `1 A, 3A`
B. `3A, 1A`
C. `1 A, 1A`
D. `3A, 3A`

Answer

D

Explanation

d. `E_1 = (2+4) xx 1 = 6 V, E_2 = (2+4) xx 2 = 12 V`

There will be no current in AB and A'B', because all these
points are at the same potential. From D to A' :
`V_(D) + 6 - 2I_(1) = V_(A), but V_(D) = V_(A') = 0 `
`implies I_1 = 3A`
For outermost loop : `6-12 = 2I_1 + 4(I_1-I_2)or I_2 = 6A`
Current through C'A' = `I_1-I_2 = 3-6 = -3A`.