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n identical cells are joined in series w...

`n` identical cells are joined in series with two cells A and B with reversed polarities. EMF of each cell is E and internal resistance is r. Potential difference across cell A or B is (n gt 4)

A

`(2epsilon(n-2))/(n)`

B

`(2epsilon(n+2))/n`

C

`(4epsilon)/n`

D

`(2epsilon)/n`

Text Solution

Verified by Experts

The correct Answer is:
A
a. The two opposite cells A and B will cancel two more cells, so
net emf will be `n-4`. So current is
`I = ((n-4)epsilon)/(nr)`
Now pd across A or B is
`I epsilon + Ir` (as they will be in charging state) ,brgt `= epsilon = ((n-4)epsilon)/n = 2epsilon (1-2/n) = (2epsilon(n-2))/n`.
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