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In circuit shown in figure, terminal X i...

In circuit shown in figure, terminal X is brought from point A to B. Then reading of ammeter
.

A

increases

B

decreases

C

first increases then decreases

D

first decreases then increases

Text Solution

Verified by Experts

The correct Answer is:
D
d. When X is at A or B:
Raeading of ammeter `I_(0) = epsilon/R`
`R = x+y` or `I_(0 )= epsilon/(x+y)`
,
When sliding key is at any other position
`I_(1) = epsilon/((R_0x)/(R_0+x) +y)`
`Reading of ammeter `I = I_(1) (R_0)/(R_0+x)`
`= (epsilon(R_0+x))/([R_0x+(R_0+y)] (R_0+x))`
`= (epsilonR_0)/(R_0(x+y)+xy) = (epsilon)/((x+y)+(xy)/(R_0))` ,brgt Hence `I' ltI_0`
Hence the reading of ammeter first decreases then increases.
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