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For the circuit shown in the figure dete...

For the circuit shown in the figure determine the charge on capacitor in steady state.

A

4 C

B

6 C

C

1 C

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
b. In steady state, the capacitor is fully charged and is treated as
open circuit, so no current flows through branch containing
capacitor in steady state. So the circuit can be redrawn as :

Potential difference across the capacitor in steady state is
`V - 6 - V = -6V`
(Negative sign signifies that left hand plate is of negative polarity.)
Charge = CV = `1 xx 6 = 6mC` .
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