Let the x-z plane be the boundary between two transparent media. Medium 1 in `zge0` has a refractive index of `sqrt2` and medium 2 with `zlt0` has a refractive index of `sqrt3`. A ray of light in medium 1 given by the vector `vecA=6sqrt3hati+8sqrt3hatj-10hatk` is incident on the plane of separation. The angle of refraction in medium 2 is:

Explanation

To solve the problem, we need to find the angle of refraction \( r \) when a ray of light passes from medium 1 to medium 2 at the boundary defined by the x-z plane. Here are the steps to solve the problem:

### Step 1: Identify the vectors and refractive indices
The incident ray in medium 1 is given by the vector:
\[ \vec{A} = 6\sqrt{3} \hat{i} + 8\sqrt{3} \hat{j} - 10 \hat{k} \]
The refractive index of medium 1 (\( \mu_1 \)) is \( \sqrt{2} \) and for medium 2 (\( \mu_2 \)) it is \( \sqrt{3} \).
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