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Find the focal length of the lens shown ...

Find the focal length of the lens shown in Fig . The radii of curvature of both the surfaces are equal to R.

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For an object placed at infinity, the image after first refraction will be formed at `v_(1)`
`:. (mu_(2))/(v_(1))-(mu_(1))/(-oo)=(mu_(2)-mu_(2))/(+R)` (i)
The image second refraction will be found at `v_(2)`
`:. (mu_(3))/(v_(2))-(mu_(2))/(v_(1))=(mu_(3)-mu_(1))/(+R)` (ii)
Adding (i) and (ii) `(mu_(3))/(v_(2))=(mu_(3)-mu_(1))/(R)`
`rArr v_(2)=(mu_(3)R)/(mu_(3)-mu_(1))`
Therefore, focal length will be `(mu_(3) R)/(mu_(3)-mu_(1))` .
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Knowledge Check

  • Assertion : The focal length of an equiconvex lens placed in air is equal to radius of curvature of either face. Reason : For an equiconvex lens radius of curvature of both the faces is same.

    A
    If both assertion and reason are true and reason is the correct explanation of assertion.
    B
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    C
    If assertion is true but reason is false.
    D
    If both assertion and reason are false.
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