Home
Class 12
PHYSICS
Refracting angle o f a prism A=60^@ and ...

Refracting angle o f a prism `A=60^@` and its refractive index is `n=3//2`. What is angle of incidence i to get minimum deviation. Also, find the minimum deviation. Assume the surrounding medium to be air `(n=1)`.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Understand the given data We are given: - Refracting angle of the prism, \( A = 60^\circ \) - Refractive index of the prism, \( n = \frac{3}{2} \) - Refractive index of air, \( n_{air} = 1 \) ...
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise1.5|22 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise1.6|15 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise1.3|25 Videos
  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS ENGLISH|Exercise dpp 3.3|15 Videos
  • HEATING EFFECT OF CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Thermal Power in Resistance Connected in Circuit|27 Videos

Similar Questions

Explore conceptually related problems

A prism of apex angle A=60^@ has the refractive index mu=sqrt2. The angle of incidence for minimum deviation is

If the refracting angle of a prism is 60^@ and the minimum deviation is 30^@ , then the angle of incidence is

The refracting angle of a prism is A and refractive index of the material of prism is cot(A//2) . The angle of minimum deviation will be

The refracting angle of a prism is A and refractive index of the material of prism is cot(A//2) . The angle of minimum deviation will be

The refracting angle of a prism is A and refractive index of the material of prism is cot(A//2) . The angle of minimum deviation will be

The refracting angle of a prism is A and refractive index of the material of prism is cot(A//2) . The angle of minimum deviation will be

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A/2) . The angle of minimum deviation is

A prism of refractive index m and angle A is placed in the minimum deviation position. If the angle of minimum deviation is A , then the value of A in terms of m is

The angle of a prism is 60^(@) and its refractive index is sqrt(2) . The angle of minumum deviation sufferred by a ray of light in passing through it is

The refracting angle of the prism is 60^@ and the refractive index of the material of the prism is sqrt(3) . Calculate the angle of minimum deviation in degree.