A lens(n=1.5) is 5cm thick and the radii of curvature of its object is placed at a distance of 12cm from the surface whose radius of curvature is 10cm. How far beyond the other surface is the image formed?

Explanation

To solve the problem step by step, we will use the lens maker's formula and the concept of refraction at spherical surfaces.

### Step 1: Identify the Given Values
- Refractive index of the lens, \( n = 1.5 \)
- Thickness of the lens, \( t = 5 \, \text{cm} \)
- Distance of the object from the first surface, \( u = -12 \, \text{cm} \) (negative as per sign convention)
- Radius of curvature of the first surface, \( R_1 = +10 \, \text{cm} \) (positive as it is convex)
- Radius of curvature of the second surface, \( R_2 = -25 \, \text{cm} \) (negative as it is concave)
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