A spherical surface of radius R ssparates two media of refractive indices `mu_(1)` and `mu_(1)` as shown in figure., Where should an object be placed in medium 1 so that a real image is formed in medium 2 at the same distance?

Explanation

Let x be the distance of the object from the pole in medium 1.
Here we have , `u=-x, v=+x and R=+R`
Using the equation, we get `(mu_(2))/(+x)-(mu_(1))/(-x) =(mu_(2)-mu_(1))/(+R)`
or `x=((mu_(2)+mu_(1))/(mu_(2)-mu_(1)))R`
Note that the real image is formed only when `mu_(2) gt mu_(1)` .