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There is small air bubble inside a glass sphere `(mu=1.5)` of radius 10 cm. The bubble is 4.0 cm below the surface and is viewed normally from the outside figure. Find the apparent depth of the bubble

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The observer sees the image formed due to refraction at the spherical surface when the light formt he bubble goes from the glass to the air.
Here, `u=-4.0cm, R=-10cm, mu=1.5` and `mu_(2)=1`.
`(1)/(v)+(-1.5)/(-4.0cm)=(1-1.5)/(-10cm)`
`(1)/(v)=(0.5)/(10cm)-(1.5)/(4.0cm)`
`v=-3.0cm` .
Thus, the bublle will appear `3.0 cm` below the surface.
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CENGAGE PHYSICS ENGLISH-GEOMETRICAL OPTICS-Exercise1.5
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