A converging bundle of rays travel from water (refractive index `4//3` ) to glass (refractive index 1.5) through a convex interface of radius 16cm. In the absence of the interface, The rays would have converged to a point 32 cm from the pole of the interface. Where will the rays actually meet after refraction?

Explanation

To solve the problem, we will use the formula derived from the lens maker's equation for refraction at a spherical surface. The formula is given by:

\[ \frac{n_2}{V} - \frac{n_1}{U} = \frac{n_2 - n_1}{R} \]

Where:
- \( n_1 \) is the refractive index of the medium from which the rays are coming (water, \( \frac{4}{3} \)).
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