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A slit of width d is placed in front of ...

A slit of width d is placed in front of a l ens of focal length 0.5m and is illuminated normally with light of wavelength `5.89xx10^(-7)m`. The first diffraction minima on either side of the central diffraction maximum are separated by `2xx10^(-3)m` . The width d of the slit is `"_________"`m.

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To solve the problem, we need to find the width \( d \) of the slit given the parameters of the system. We will use the formula for the position of the first diffraction minima in a single-slit diffraction pattern. ### Step-by-Step Solution: 1. **Identify the given values:** - Wavelength \( \lambda = 5.89 \times 10^{-7} \, \text{m} \) - Focal length of the lens \( f = 0.5 \, \text{m} \) - Distance between the first diffraction minima on either side of the central maximum \( y = 2 \times 10^{-3} \, \text{m} \) ...
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