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Two coherent sources of light of intens...

Two coherent sources of light of intensity ratio `beta` produce interference pattern. Prove that in the interferencepattern
`(I_(max) - I_(min))/(I_(max) + (I_(min))) = (2 sqrt beta)/(1 + beta)`
where `I_(max)` and `I_(min)` are maximum and mininum intensities in the resultant wave.

Text Solution

AI Generated Solution

To prove the given expression \((I_{max} - I_{min})/(I_{max} + I_{min}) = \frac{2\sqrt{\beta}}{1 + \beta}\), where \(I_{max}\) and \(I_{min}\) are the maximum and minimum intensities in the interference pattern produced by two coherent sources of light with intensity ratio \(\beta\), we can follow these steps: ### Step 1: Define the Intensities Let the intensities of the two coherent sources be \(I_1\) and \(I_2\). According to the problem, we have the intensity ratio: \[ \frac{I_1}{I_2} = \beta \] This implies: ...
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Knowledge Check

  • The two coherent sources with intensity ratio beta produce interference. The fringe visibility will be

    A
    `(2 sqrt(beta))/(1+beta)`
    B
    `2beta`
    C
    `(2)/(1+beta)`
    D
    `(sqrt(beta))/(1+beta)`
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