Refractive index of a thin soap film of a uniform thickness is 1.34. Find the smallest thickness of the film that gives in interference maximum in the reflected light when light of wavelength `5360 Å` fall at normal incidence.

Explanation

To find the smallest thickness of a thin soap film that gives an interference maximum in the reflected light, we can follow these steps:

### Step 1: Understand the condition for constructive interference
For constructive interference in thin films, the condition is given by:
\[ 2 \mu t = (n + \frac{1}{2}) \lambda \]
where:
- \( \mu \) is the refractive index of the film,
- \( t \) is the thickness of the film,
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