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In Young'double-slit interference experi...

In Young'double-slit interference experiment, if the slit separation is made threefold, the fringe width becomes

A

sixfold

B

threefold

C

`3//6` - fold

D

`1//3` - fold

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The correct Answer is:
To solve the problem regarding the change in fringe width when the slit separation in Young's double-slit experiment is increased threefold, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Fringe Width:** The fringe width (β) in Young's double-slit experiment is given by the formula: \[ \beta = \frac{\lambda D}{d} \] where: - \( \lambda \) = wavelength of light used, - \( D \) = distance from the slits to the screen, - \( d \) = separation between the slits. 2. **Identify the Change in Slit Separation:** According to the problem, the slit separation \( d \) is increased threefold. This means: \[ d' = 3d \] where \( d' \) is the new slit separation. 3. **Calculate the New Fringe Width:** Substitute the new slit separation \( d' \) into the fringe width formula: \[ \beta' = \frac{\lambda D}{d'} \] Replacing \( d' \) with \( 3d \): \[ \beta' = \frac{\lambda D}{3d} \] 4. **Relate the New Fringe Width to the Original:** Now, we can express the new fringe width in terms of the original fringe width: \[ \beta' = \frac{1}{3} \cdot \frac{\lambda D}{d} = \frac{1}{3} \beta \] This shows that the new fringe width \( \beta' \) is one-third of the original fringe width \( \beta \). 5. **Conclusion:** Therefore, when the slit separation is increased threefold, the fringe width becomes: \[ \beta' = \frac{1}{3} \text{ of the original fringe width} \] ### Final Answer: The fringe width becomes \( \frac{1}{3} \) fold of the original fringe width.

To solve the problem regarding the change in fringe width when the slit separation in Young's double-slit experiment is increased threefold, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Formula for Fringe Width:** The fringe width (β) in Young's double-slit experiment is given by the formula: \[ \beta = \frac{\lambda D}{d} ...
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