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In Young's doulbe-slit experiment the se...

In Young's doulbe-slit experiment the separation between two coherent sources `S_(1)` and `S_(2)` is d and the distance between the source and screen is D. In the interference pattern, it is found that exactly in front of one slit, there occurs a minimum. Then the possible wavelengths used in the experiment are

A

`lambda = (d^(2))/(D) , (d^(2))/(3D) , (d^(2))/(5D)`

B

`lambda = (d^(2))/(D) , (d^(2))/(5D) , (d^(2))/(9D)`

C

`lambda = (d^(2))/(D) , (d^(2))/(2D) , (d^(2))/(3D)`

D

`lambda = (d^(2))/(3D) , (d^(2))/(7D) , (d^(2))/(11D)`

Text Solution

Verified by Experts

The correct Answer is:
a

`y = (d)/(2) = (2(n - 1) D lambda)/(2d)`
`implies lambda = (d^(2))/(D(n - 1)) , n = 1, 2, 3`
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