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In Young's double-slit experiment the an...

In Young's double-slit experiment the angular width of a fringe formed on a distant screen is `1^(@)`. The wavelength of light used is `6000 Å`. What is the spacing between the slits?

A

344 mm

B

0.1344mm

C

0.0344 mm

D

0.034 mm

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The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the relationship between angular width, fringe width, and slit separation In Young's double-slit experiment, the angular width of a fringe (θ) is related to the fringe width (β) and the distance between the slits (d) by the formula: \[ \theta = \frac{\beta}{D} \] where \(D\) is the distance from the slits to the screen. ### Step 2: Express fringe width in terms of wavelength and slit separation The fringe width (β) can be expressed as: \[ \beta = \frac{\lambda D}{d} \] where \(λ\) is the wavelength of light used. ### Step 3: Substitute fringe width into the angular width formula Substituting the expression for fringe width into the angular width formula gives: \[ \theta = \frac{\lambda D}{dD} = \frac{\lambda}{d} \] Thus, we can rearrange this to find the slit separation: \[ d = \frac{\lambda}{\theta} \] ### Step 4: Convert the angular width from degrees to radians The angular width given is \(1^\circ\). We need to convert this to radians: \[ \theta = 1^\circ = \frac{\pi}{180} \text{ radians} \] ### Step 5: Substitute the known values into the equation Now we can substitute the values of \(λ\) and \(θ\) into the equation for \(d\): - Wavelength \(λ = 6000 \text{ Å} = 6000 \times 10^{-10} \text{ m} = 6 \times 10^{-7} \text{ m}\) - Angular width \(θ = \frac{\pi}{180} \text{ radians}\) Substituting these values into the equation for \(d\): \[ d = \frac{6 \times 10^{-7}}{\frac{\pi}{180}} \] ### Step 6: Calculate the value of d Now, calculate \(d\): \[ d = 6 \times 10^{-7} \times \frac{180}{\pi} \] Using \(\pi \approx 3.14\): \[ d \approx 6 \times 10^{-7} \times \frac{180}{3.14} \approx 6 \times 10^{-7} \times 57.3 \approx 3.44 \times 10^{-5} \text{ m} \] ### Step 7: Convert the result to millimeters To convert meters to millimeters: \[ d = 3.44 \times 10^{-5} \text{ m} = 0.0344 \text{ mm} \] ### Final Answer The spacing between the slits is approximately \(0.0344 \text{ mm}\). ---

To solve the problem, we will follow these steps: ### Step 1: Understand the relationship between angular width, fringe width, and slit separation In Young's double-slit experiment, the angular width of a fringe (θ) is related to the fringe width (β) and the distance between the slits (d) by the formula: \[ \theta = \frac{\beta}{D} \] where \(D\) is the distance from the slits to the screen. ...
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