When light of sufficiently high frequency is incident on a metallic surface, electrons are emitted from the metallic surface. This phenomenon is called photoelectric emission. Kinetic energy of the emitted photoelectrons depends on the wavelength of incident light and is independent of the intensity of light. Number of emitted photoelectrons depends on intensity. `(hv-phi)` is the maximum kinetic energy of emitted photoelectron (where `phi` is the work function of metallic surface). Reverse effect of photo emission produces X-ray. X-ray is not deflected by electric and magnetic fields. Wavelength of a continuous X-ray depends on potential difference across the tuve. Wavelength of charasteristic X-ray depends on the atomic number.
Q. A monochromatic light is used in a photoelectric experiment on photoelectric effect. The stopping potential

Options

A. is related to the mean wavelength
B. is related to the shortest wavelength
C. is related to the maximum kinetic energy of emitted photoelectrons
D. intensity of incident light

Explanation

To solve the problem regarding the photoelectric effect and the stopping potential, we will follow these steps:

### Step 1: Understand the Photoelectric Effect
The photoelectric effect occurs when light of sufficient frequency strikes a metallic surface, causing the emission of electrons. The energy of the incident photons is given by \( E = h\nu \), where \( h \) is Planck's constant and \( \nu \) is the frequency of the light.

### Step 2: Relate Photon Energy to Work Function
The maximum kinetic energy (\( KE_{max} \)) of the emitted photoelectrons can be expressed using Einstein's photoelectric equation:
\[ KE_{max} = h\nu - \phi \]
where \( \phi \) is the work function of the metal.

### Step 3: Define Stopping Potential
The stopping potential (\( V_0 \)) is the potential difference needed to stop the emitted electrons from reaching the anode. The relationship between the stopping potential and the maximum kinetic energy is given by:
\[ KE_{max} = eV_0 \]
where \( e \) is the charge of the electron.

### Step 4: Combine the Equations
From the above equations, we can equate the maximum kinetic energy to the stopping potential:
\[ eV_0 = h\nu - \phi \]
Rearranging gives:
\[ V_0 = \frac{h\nu - \phi}{e} \]

### Step 5: Relate Stopping Potential to Wavelength
Using the relation \( \nu = \frac{c}{\lambda} \) (where \( c \) is the speed of light and \( \lambda \) is the wavelength), we can substitute \( h\nu \) with \( \frac{hc}{\lambda} \):
\[ V_0 = \frac{hc/\lambda - \phi}{e} \]
This can be rewritten as:
\[ V_0 = \frac{hc}{e\lambda} - \frac{\phi}{e} \]

### Step 6: Analyze the Options
Now we can analyze the statements regarding the stopping potential:
1. **Stopping potential is related to the mean wavelength** - This is incorrect; it is related to the maximum kinetic energy.
2. **Stopping potential is related to the maximum kinetic energy of emitted photoelectrons** - This is correct.
3. **Stopping potential depends on the intensity of incident light** - This is incorrect; intensity affects the number of emitted electrons, not their energy.

### Conclusion
The stopping potential is primarily related to the maximum kinetic energy of the emitted photoelectrons, not to the intensity of the light or the mean wavelength.