What is the angular momentem of an electron in Bohr's hydrogen atom whose energy is `- 3.5eV`?

Explanation

To find the angular momentum of an electron in a Bohr hydrogen atom with an energy of -3.5 eV, we can follow these steps:

### Step 1: Relate Energy to Principal Quantum Number
The energy of an electron in a hydrogen atom is given by the formula:
\[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \]
where \(E_n\) is the energy at the principal quantum number \(n\).
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