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Find the quantum number `n` corresponding to the excited state of He^(+) ion if on transition to the ground state that ion emits two photons in succession with wavelengths state that ion emits two photons in succession with wavelengths`1026.7 and 304Å. (R = 1.096 xx 10^(7)m^(_1)`

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To solve the problem, we need to find the quantum number \( n \) corresponding to the excited state of the He\(^+\) ion when it emits two photons with given wavelengths during its transition to the ground state. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Wavelength of the first photon, \( \lambda_1 = 1026.7 \) Å - Wavelength of the second photon, \( \lambda_2 = 304 \) Å - Rydberg constant, \( R = 1.096 \times 10^7 \, \text{m}^{-1} \) ...
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