The energy of an electron in an excited hydrogen atom is `- 3.4 e V`. Calculate the angular momentum . Given : Rydbrg's `R = 1.09737 xx 10^(-7) m^(-1)`. Plank's constant `h = 6.626176 xx 10^(-34) J - s`, speed of light`c = 3 xx 10^(8) m s^(-1).

Explanation

To solve the problem, we need to calculate the angular momentum of an electron in an excited hydrogen atom given its energy. The energy of the electron is provided as \(-3.4 \, \text{eV}\).

### Step-by-Step Solution:

**Step 1: Identify the Principal Quantum Number (n)**
The energy levels of the hydrogen atom are given by the formula:
\[
E_n = -\frac{13.6 \, \text{eV}}{n^2}
...