Find the frequency of light which ejects electrons from a metal surface. Fully stopped by a retarding potential of `3 V`, the photoelectric effect begins in this metal at a frequency of `6xx10^(14)Hz`. Find the work function for this metal. (Given `h=6.63xx10^(-34)Js`).

Explanation

To solve the problem, we need to find the work function of the metal and the frequency of light that ejects electrons from the metal surface. We will use the provided information step by step.

### Step 1: Calculate the Work Function (Φ)

The work function (Φ) can be calculated using the formula:
\[ \Phi = h \cdot \nu_0 \]
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