Home
Class 12
PHYSICS
An X-ray tube operates at 20k V. Find th...

An X-ray tube operates at `20k V`. Find the maximum speed of the electron strinking the anode , given the charge of electron is `1.6 xx 10^(-19)` coulomb and mass of electron is `9 xx 10^(-31) kg`.

Text Solution

Verified by Experts

When an electron of charge `e` is accelerated through a potential different `V`, it acquired energy `e V`. If `m` be the mass of the electron and `v_(max)` the maximum speed of electron , then
`(1)/(2) m v_(max)^(2) = e V` or `v_(max) = sqrt(((2 e V)/(m)))`
Subsitituting the given value , we get
`v_(max) = sqrt(((2 xx (1.6 xx 10^(-19)) xx 20.000)/(9 xx 10^(-31))))`
`= 8.4 xx 10^(7) ms^(-1)`
Promotional Banner

Topper's Solved these Questions

  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise Subject|17 Videos

  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|187 Videos

  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 4.1|15 Videos

  • ALTERNATING CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|10 Videos

  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

Similar Questions

Explore conceptually related problems

The charge of an electron is 1.6 xx 10^(-19) coulombs. What will be the value of charge of Na^(+) ion

An electron is accelerated under a potential difference of 182 V. the maximum velocity of electron will be (Given, charge of an electron is 1.6xx10^(-19)C ms^(-1) and its mass is 9.1xx10^(-31)kg )

Calculate the uncertainty in the position (Delta x) of an electron if Delta v is 0.1 % .Take the velocity of electron = 2.2 xx10^(6) ms^(-1) and mass of electron as 9.108 xx 10^(-31)kg

Molar mass of electron is nearly : (N_(A) = 6 xx 10^(23)) , mass of e^(-) = 9.1 xx 10^(-31)Kg

The mass of half mole of electrons is about (Given: Mass of electron =9.1 xx10^(-28) g)

The ratio of electrostatic and gravitational force acting between electron and proton separated by a distance 5 xx 10^(-11)m , will be (charge on electron = 1.6 xx 10^(-19)C , mass of electron = 9.1 xx 10^(-31) kg , mass of proton = 1.6 xx 10^(-27) kg, G = 6.7 xx 10^(-11) N - m^(2)//kg^(2) )

In an experiment ,electrons are accelerated from rest, by applying a voltage of 500 V.Calculate the radius of the path if a magnetic field 100 m T is then applied .Charge of the electron =1.6 xx 10^-19 C Mass of the electron =9.1 xx 10 ^(-31) Kgl

The speed of the electron in the hydrogen atom is approximately 2.2 xx 10^(6) m//s . What is the centripetal force acting on the electron ifthe radius of the circular orbit is 0.53 xx 10^(-10) m ?Mass of the electron is 9.1 xx 10^(-31) kg

The kinetic energy of an electron is 4.55 xx 10^(-25) J .The mass of electron is 9.1 xx 10^(-34) kg . Calculate velocity of the electron.

In the Bohr model of hydrogen atom, the electron is treated as a particle going in a circle with the centre at the proton. The proton itself is assumed to be fixed in an inertial frame. The centripetal force is provided by the Coloumb attraction. In the ground state, the electron goes round the proton in a circle of radius 5.3xx10^-11m . Find the speed of the electron in the ground state. Mass of the electron =9.1xx10^-31 kg and charge of the electron = 1.6xx10^-19C .