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In an ordianary atom, as a first approxi...

In an ordianary atom, as a first approximation, the motion of the nucleus can be ignored. In a positronium atom a positronreplaces the proton of hydrogen atom. The electron and positron masses are equal and , therefore , the motion of the positron cannot be ignored. One must consider the motion of both electron and positron about their center of mass. A detailed analyasis shows that formulae of Bohr's model apply to positronium atom provided that we replace `m_(e)` by what is known reduced mass is `m_(e)//2`.
If the Rydberg constant for hydrogen atom is `R` , then the Rydberg constant for positronium atom is

A

`2 R`

B

`R`

C

` R//2`

D

`4 R`

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To solve the problem, we need to determine the Rydberg constant for the positronium atom based on the information given about the hydrogen atom and the properties of positronium. ### Step-by-Step Solution: 1. **Understanding the Rydberg Constant for Hydrogen**: The Rydberg constant \( R \) for hydrogen is given by the formula: \[ R = \frac{2 \pi^2 m_e k^2 e^4}{h^3 c} \] where \( m_e \) is the mass of the electron, \( k \) is Coulomb's constant, \( e \) is the charge of the electron, \( h \) is Planck's constant, and \( c \) is the speed of light. 2. **Identifying the Positronium Atom**: In the positronium atom, we have an electron and a positron (which has the same mass as the electron). The reduced mass \( \mu \) of the system (electron and positron) is given by: \[ \mu = \frac{m_e m_e}{m_e + m_e} = \frac{m_e^2}{2m_e} = \frac{m_e}{2} \] 3. **Rydberg Constant for Positronium**: The formula for the Rydberg constant for positronium \( R' \) can be expressed similarly to that of hydrogen, but we replace \( m_e \) with the reduced mass \( \mu \): \[ R' = \frac{2 \pi^2 \mu k^2 e^4}{h^3 c} \] Substituting \( \mu = \frac{m_e}{2} \) into the equation: \[ R' = \frac{2 \pi^2 \left(\frac{m_e}{2}\right) k^2 e^4}{h^3 c} \] 4. **Simplifying the Expression**: This can be simplified to: \[ R' = \frac{1}{2} \cdot \frac{2 \pi^2 m_e k^2 e^4}{h^3 c} = \frac{1}{2} R \] 5. **Conclusion**: Therefore, the Rydberg constant for the positronium atom is: \[ R' = \frac{R}{2} \] ### Final Answer: The Rydberg constant for the positronium atom is \( \frac{R}{2} \). ---

To solve the problem, we need to determine the Rydberg constant for the positronium atom based on the information given about the hydrogen atom and the properties of positronium. ### Step-by-Step Solution: 1. **Understanding the Rydberg Constant for Hydrogen**: The Rydberg constant \( R \) for hydrogen is given by the formula: \[ R = \frac{2 \pi^2 m_e k^2 e^4}{h^3 c} ...
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In an ordianary atom, as a first approximation, the motion of the nucleus can be ignored. In a positronium atom a positronreplaces the proton of hydrogen atom. The electron and positron masses are equal and , therefore , the motion of the positron cannot be ignored. One must consider the motion of both electron and positron about their center of mass. A detailed analyasis shows that formulae of Bohr's model apply to positronium atom provided that we replace m_(e) by what is known reduced mass is m_(e)//2 . The orbital radius of the first excited level of postronium atom is

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CENGAGE PHYSICS ENGLISH-ATOMIC PHYSICS-Linked Comprehension
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