In a set of experiment on a hydrogen on a hypotherical one-electron atom, the wavelength of the photons emitted from transition ending in the ground state `(n = 1)` are shown in the energy level diagram

`lambda_(5 to 1) = 73.86 nm`
`lambda_(4 to 1) = 75.63 nm`
`lambda_(3 to 1) = 79.76 nm`
`lambda_(2 to 1) = 94.54 nm`
The possible energy of the atom in `n = 3` cannot be

Options

A. `-19.5 eV`
B. `-0.4875 eV`
C. `-0.121 eV`
D. `-7.8 eV`

Answer

D

Explanation

The possible energy of the atom in `n = 3`.
`E_(03) = (E_(3))/(Z^(2))`
For `Z = 1, E_(03) = - 1.95 eV`
`Z = 2, E_(03) = - 0.4875 eV`
`Z = 3, E_(03) = - 0.2166 eV`
`Z = 4, E_(03) = - 0.121 eV`