The shortest wavelength of the Brackett series of hydrogen like atom (atomic number =Z) is the same as the shortest wavelength of the Blamer series of hydrgeon atom . The value ofn Z is

Answer

2

Explanation

The shortest wavelength of Bracket series is corresponding to transition of electron between `n_(1) = 4 and n_(2) = oo`
Similarly , the shortest wavelength of Bracket series is corresponding to transition of electron between `n_(1) = 2 and n_(2) = oo`
`(Z)^(2) ((13.6)/(16)) = ((13.6)/(4)) or Z= 2`