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The wavlength of K(alpha), X-rays produc...

The wavlength of `K_(alpha),` X-rays produced by an X-ray tube 0.76Å . The atomic number of the anode material of the tube is

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The correct Answer is:
b
`(1)/(lambda) = R (z - 1) ^(2) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
Since for `K_(alpha), n_(2) = 2 = n_(1) = 1`
`:. (1)/(0.76 xx 10^(-10)) = 1.097 (z - 1) ^(2) [(1)/(1^(2)) - (1)/(2^(2))]`
`implies z - 1 = 40 implies z = 41`
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