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The key feature of Bohr's spectrum of hy...

The key feature of Bohr's spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of a diatomic molecule assuming it to be rigid.The rule to be applied is Bohr's quantization condition.
In a `CO` molecule, the distance between `C (mass = 12 a. m. u ) and O (mass = 16 a.m.u)` where `1 a.m.u = (5)/(3) xx 10^(-27) kg , `is close to

A

`2.4 xx 10^(-10) m`

B

`1.9 xx 10^(-10) m`

C

`1.3 xx 10^(-10) m`

D

`4.4 xx 10^(-10) m`

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To solve the problem of finding the distance between the carbon (C) and oxygen (O) atoms in a CO molecule using Bohr's quantization condition, we will follow these steps: ### Step 1: Understanding the Masses The masses of carbon and oxygen are given as: - Mass of Carbon (C) = 12 a.m.u - Mass of Oxygen (O) = 16 a.m.u We also know that: ...
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The key feature of Bohr's spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of a diatomic molecule assuming it to be rigid.The rule to be applied is Bohr's quantization condition. A diatomic molecule has moment of inertia I . By Bohr's quantization condition its rotational energy in the n^(th) level ( n = 0 is not allowed ) is

The key feature of Bohr's spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of a diatomic molecule assuming it to be rigid.The rule to be applied is Bohr's quantization condition. A diatomic molecule has moment of inertia I . By Bohr's quantization condition its rotational energy in the n^(th) level ( n = 0 is not allowed ) is

The key feature of Bohr's spectrum of hydrogen atom is the quantization of angular momentum when an electron is revolving around a proton. We will extend this to a general rotational motion to find quantized rotational energy of a diatomic molecule assuming it to be rigid.The rule to be applied is Bohr's quantization condition. it is found that the excitation from ground to the first excited state of rotation for the CO molecule is close to (4)/(pi) xx 10^(11) Hz then the moment of inertia of CO molecule about its center of mass is close to (Take h = 2 pi xx 10^(-34) J s )

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