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A conducting rod of mass m and length ...

A conducting rod of mass m and length l is placed over a smooth horizontal surface . A unifrom magnetic field B is acting perpendicular to the rod. Charge q is suddenly passed throught the red it accquire an initnal velocity on the surface , then q is equal to

A

`(2mv)/(bl)`

B

`(Bl)/(2mv)`

C

`(mv)/(bl)`

D

`(Blv)/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
c
Using, impulse=change in linear momentum, we have
`intFdt=mv or int (iBl)dt=mv`
or `Blq=mv (as intidt=q)`
`:. q=(mv)/(Bl)`
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