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Let current i=2A be flowing in each part...

Let current `i=2A` be flowing in each part of a wire frame as shown in Fig. 1.138. The frame is a combination of two equilateral triangles ACD and CDE of side 1 m. It is placed in uniform magnetic field ` B= 4 T` acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is

A

24 N

B

zero

C

16 N

D

8 N

Text Solution

Verified by Experts

The correct Answer is:
a
`F_(CAD)=F_(CD)=F_(CAD)`
`:.` Net force on the frame `=3F_(CD)`
`=(3)(2)(1)(4)=24N (F=ilB)`.
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