A small block of mass m, having charge q, is placed on a frictionless inclined plane making an angle `theta` with the horizontal. There exists a uniform magnetic field B parallel to the inclined plane but perpendicular to the length of spring. If m is slightly pulled on the incline in downward direction, the time period of oscillation will be (assume that the block does not leave contact with the plane)

Options

A. `2pisqrt(m/K)`
B. `2pisqrt((2m)/K)`
C. `2pisqrt((qB)/K)`
D. `2pisqrt((qB)/(2K))`

Answer

a

Explanation

There will be no effect of magnetic force on time period
because the magnetic force will be perpendicular to the
inclined plane.