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A current I = 10 A flows in a ring of ra...

A current I = 10 A flows in a ring of radius `r_(0) =15cm` made of a very thin wire. The tensile strength of the wire is equal to T = 1.5 N. The ring is placed in a magnetic field, which is perpendicular to the plane of the ring so that the forces tend to break the ring. Find the magnetic field at which the ring is broken

Text Solution

Verified by Experts

The correct Answer is:
1
For the equilibrium of a small part of semicircular arc subtending
an angle of `d theta` at the centre,
or, `2Tsin((d theta)/2)=Bir_0 d theta`
`B=T/(Ir_0)=1.5/((10)(0.15))=1T`
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