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A wire ABCDEF (with each side of length ...

A wire ABCDEF (with each side of length L) bent as shown in figure. The wire carrying a current I is placed in a uniform magnetic induction B parallel to the positive y-direction. The force experienced by the wire in the z-direction is

Text Solution

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We use the formula `vecF=I(veclxxvecB) implies F=ILBsin theta`
For sides FE and BA, the angle will be
`180^@ and 0^@`, respectively.
`:.F=0`
For sides DE and CB, the forces will be
ILB but opposite in directions, in +X and
-X direction, respectively.
The net force due to these two sides will
be zero.
The force due to current inside DC will be `ILB sin90^@=ILB` in
+Z direction (according to Fleming's left hand rule.)
So net force on the wire is ILB is positive z direction.
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