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The magnetic field at the centre of an ...

The magnetic field at the centre of an equilateral triangular loop of side 2L and carrying a current i is

A

`(9mu_0i)/(4piL)`

B

`(3sqrt3mu_0i)/(4piL)`

C

`(2sqrt3mu_0i)/(piL)`

D

`(3mu_0i)/(4piL)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) Magnetic field at O is
`B=[(mu_0)/(4pi) i/r(sin60^@+sin60^@)]`

`=3((mu_0)/(4pi)) (i)(sqrt3)((sqrt3))/L=(9mu_0i)/(4piL)`
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