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A steady current is set up in a cubic ne...

A steady current is set up in a cubic network composed of wires of equal resistance and length d as shown in Fig. What is the magnetic field at centre P due to the cubic network?

A

`(mu_0)/(4pi) (2I)/d`

B

`(mu_0)/(4pi) (3I)/(sqrt2d)`

C

0

D

`(mu_0)/(4pi) ( theta piI)/d`

Text Solution

Verified by Experts

The correct Answer is:
C
(c) Net magnetic field at P will be zero, because the magnetic
field at centre P is cancelled by opposite pairs like AD-EF,
etc.
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Knowledge Check

  • An equilateral triangle of side length l is formed from a piece of wire of uniform resistance. The current I is as shown in figure. Find the magnitude of the magnetic field at its centre O .

    A
    `(sqrt(3)mu_(0)I)/(2pi l)`
    B
    `(3 sqrt(3)mu_(0)I)/(2pi l)`
    C
    `(mu_(0)I)/(2pi l)`
    D
    zero

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