Home
Class 12
PHYSICS
A wire is in the form of a semicircle of...

A wire is in the form of a semicircle of radius `r`. One end is attached to an axis about which it rotates with an angular speed `omega`. The axis is normal to the plane of the semicircle. The wire is immersed in a uniform magnetic field `B` parallel to the axis. find the induced emf between points `o` and `P` of the semicircle.

Text Solution

Verified by Experts

It is given that the magnetic field is uniform.
Join the end points `O` and `P` and replace the semicircle by a straight rod of length `2r`.
We now have a straight rod rotating in a uniform magnetic field in a plane perpendicular to the magnetic field.
Therefore, the induced emf between `O` and `P` will be
`xi_(ind) = (1)/(2) Bomega(2r)^(2) = Bomegar^(2)`
From the right hand rule, we see that elcetrons will accumulate at end `O`. Therefor, end `P` is at a higher potential than `O`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS ENGLISH|Exercise Solved Example|5 Videos
  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 3.1|15 Videos
  • ELECTRICAL MEASURING INSTRUMENTS

    CENGAGE PHYSICS ENGLISH|Exercise M.C.Q|2 Videos
  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS ENGLISH|Exercise dpp 3.3|15 Videos

Similar Questions

Explore conceptually related problems

A wire is bent to form a semi-circle of radius a. the wire rotates about its one end with angular velocity omega .Axis of rotation being perpendicular to plane of the semicircle . In the space , a uniform magnetic field of induction B exists along the axis of rotation as shown . The correct statement is :

A wire is bent to form a semi-circle of radius a. The wire rotates about its one end with angular velocity omega . Axis of rotation being perpendicular to plane of the semicircle. In the space, a uniform magnetic field of induction exists along the axis of rotation as shown. The correct statement is

A straight wire of length L is bent into a semicircle. It is moved in a uniform magnetic field with speed v with diameter perpendicular to the field. The induced emf between the ends of the wire is

A ring rotates with angular velocity omega about an axis perpendicular to the plane of the ring passing through the center of the ring.A constant magnetic field B exists parallel to the axis.Find the emf induced in the ring.

a semicircle wire of radius R is rotated with constant angular velocity about an axis passing through one end and perpendicular to the plane of wire. There is a uniform magnetic field of strength B . The induced emf between the ends is

a semicircle wire of radius R is rotated with constant angular velocity about an axis passing through one end and perpendicular to the plane of wire. There is a uniform magnetic field of strength B . The induced emf between the ends is

A ring rotates with angular velocity omega about an axis perpendicula to the plane of the ring passing through the center of the ring (Fig. 3.77). A constant magnetic field B exists parallel to the axis. Find the emf induced in the ring.

A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of inertia of the rod about an axis passing through A and perpendicular to the plane of the paper is

A uniform rod of mass m is bent into the form of a semicircle of radius R. The moment of inertia of the rod about an axis passing through A and perpendicular to the plane of the paper is

A rod of length l rotates with a uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. The potential difference between the two ends of the lrod is