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A long conductin gwire AH is moved over ...

A long conductin gwire AH is moved over a conducitn triangular wire CDE with a constant velocity v in a uniform magnetic field B directed into the paper. Resistance per unit length of each wire is `rho`. Then

A

(a) a constant clockwise induced will flow in the closed loop

B

(b) an increasing anticlockwise induced current will flow in the closed loop

C

(c ) a decreasing anticlockwise induced current will flow in the closed loop

D

(d) an constant anticlockwise induced current will flow in the closed loop

Text Solution

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The correct Answer is:
D

(d) Magnetic flux in `ox` direction through the coil is increasing. Therefore, induced current will produce magnetic field in `o.` direction. Thus, the current in the loop is anticlockwise. Magnitude of induced current at any instant of time is
`I = (e)/(R) = (Bv(FG))/(rho(FG + GD + DF))`
When the wire `AH` moves downwards `FG, GD and DF` all increasing in the same ratio. Therfore, `i` is constant.
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