In fig. there exists a uniform magnetic field `B` into the plane of paper. Wire `CD` is in the shape of an arc and is fixed. `OA` and `OB` are the wires rotating with angular velocity `omega` as shown in the figure in the same plane as that of the arc about point `O`. If at some instant, `OA = OB = l` and each wire makes angle `theta = 30^(@)` with y-axis, then the current through resistance `R` is (wires `OA and OB` have no resistance)

Options

A. (a) `0`
B. (b) `(Bomegal^(2))/(R )`
C. ( c) `(Bomegal^(2))/(2R )`
D. (d) `(Bomegal^(2))/(4R )`

Answer

B

Explanation

(b) `I = ((Bomega l^(2))/(2) +(Bomega l^(2))/(2))/(R ) = (Bomega l^(2))/(R )`