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A square conductind loop, 20.0 cm on a s...

A square conductind loop, `20.0 cm` on a side placed in the same magnetic field as shown in Fig. 3.195, center of the magnetic field region, where `dB//dt = 0.035 T s^(-1)`.

The current induced in the loop if its resistance is `2.00 Omega` is

A

(a) `2.50 xx 10^(-4) A`

B

(b) `4.35 xx 10^(-4) A`

C

( c) `1.25 xx 10^(-4) A`

D

(d) `7.37 xx 10^(-4) A`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) `I = (epsilon)/(R ) = (A)/(R )(dB)/(dt) = (L^(2))/(R )(dB)/(dt)`
`= ((0.20 m)^(2)(0.0350 T //s))/(1.90 Omega)`
`= 7.37 xx 10^(-4) A`
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