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A thin semi-circular conducting ring of ...

A thin semi-circular conducting ring of radius R is falling with its plane verticle in horizontal magnetic induction `(vec B)`. At the position MNQ the speed of the ring is v, and the potential difference developed across the ring is

A

(a) zero

B

(b) `BVpiR^(2)//2` and `M` is at higher potential

C

( c) `piRBV` and `Q` is at higher potential

D

(d) `2RBV` and `Q` is at higher potential

Text Solution

Verified by Experts

The correct Answer is:
D
Induced emf: `B = ("effective length")v = B2Rv`
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