A circuit contains two inductors of self...

A circuit contains two inductors of self-inductance `L_(1)` and `L_(2)` in series (Fig) If `M` is the mutual inductence, then the effective inductance of the circuit shows will be

`L_(1) + L_(2)`

`L_(1) + L_(2) - 2M`

`L_(1) + L_(2) + M`

`L_(1) + L_(2) + 2M`

Text Solution

Verified by Experts

The correct Answer is:

When inductances are connected like this in series, then
`L = L_(1) + L_(2) + 2M`

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