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In Fig. key K is closed at t = 0. After ...

In Fig. key `K` is closed at `t = 0`. After a long time, the potential difference between `A` and `B` is zero, the value of `R` will be `[r_(1) = r_(2) = 1 Omega, E_(1) = 3 V` and `E_(2) = 7 V`, `C = 2 mu F`, `L = 4 mH`, where `r_(1)` and `r_(2)` are the internal resistances of cells `E_(1)` and `E_(2)`, respectively].

A

`(4)/(3) Omega`

B

`(4)/(9) Omega`

C

`(2)/(3) Omega`

D

`4 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(i) - ir_(1) = 0 rArr I = (E_(1))/(r_(1)) = (3)/(1) = 3 Omega`
`I = (10)/(3R + 2),(10)/(3R + 2) = 3, R = (4)/(9) Omega`
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