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Find the current passing through battery...

Find the current passing through battery immediately after key `(K)` is closed. It is given that initially all the capacitors are uncharged. (Given that `R=6Omega` and `C=4muF)`

A

`1 A`

B

`5 A`

C

`3 A`

D

`2 A`

Text Solution

Verified by Experts

The correct Answer is:
A
`R_(eq) = (5R)/(6) rArr I = (6E)/(5R) = 1 A`
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